std::ranges::borrowed_iterator_t, std::ranges::borrowed_subrange_t
来自cppreference.com
| 在标头 <ranges> 定义
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template< ranges::range R > using borrowed_iterator_t = /* 见下文 */; |
(1) | (C++20 起) |
template< ranges::range R > using borrowed_subrange_t = /* 见下文 */; |
(2) | (C++20 起) |
2) 若
R 实现 borrowed_range 则为 std::ranges::subrange<std::ranges::iterator_t<R>>,否则为 std::ranges::dangling。某些受约束算法使用这两个模板别名以避免返回潜在悬垂的迭代器或视图。
可能的实现
| borrowed_iterator_t |
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template< std::ranges::range R > using borrowed_iterator_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::iterator_t<R>, std::ranges::dangling>; |
| borrowed_subrange_t |
template< std::ranges::range R > using borrowed_subrange_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::subrange<std::ranges::iterator_t<R>>, std::ranges::dangling>; |
参阅
| (C++20) |
占位类型,指示不应返回迭代器或子范围,因为它可能悬垂 (类) |